If the width is doubled and the length is decreased by 2 fee. Log On, question 161047This question is from textbook Amsco's Integrated Algebra 1 : Hi I really need help on my math homework.
Amsco - Integrated Algebra I. The publisher of the new amsco Algebra book, being used at the Hs is allowing us to post the book in PDF format to our website. Displaying 1 - 3 of 3, displaying 1 - 3 of 3. This is a free lesson from our course in Amsco s Integrated Algebra. (n-r1) For example: number of permutations of six objects, taken two at a time is 30. Permutation, permutations factorials, math,algebra, video,math help, quizzes, practice.
Here is the question: The length of a rectangle exceeds its width by 4 feet. If the width is doubled and the length is decreased by 2 feet, a new rectangle is formed whose perimeter is 8 feet more than the perimeter of the original rectangle.
Thanks for help. This question is from textbook Amsco's Integrated Algebra 1, answer by ptaylor(2175) (Show Source You can put this solution on your website! YOU ARE absolutely right IN your approach SO FAR: Now given what you have done, we know that the perimeter of a rectangle is 2w2l.